3(x+4)^2-2=16

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Solution for 3(x+4)^2-2=16 equation: 



3(x+4)^2-2=16

We move all terms to the left:

3(x+4)^2-2-(16)=0

We add all the numbers together, and all the variables

3(x+4)^2-18=0

We move all terms containing x to the left, all other terms to the right

3(x+4)^2=18

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